(-1/2x²y)^5÷(1/2x²y)
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
先化简再求值:(x-2y)²-(x+2y)(x-2y)-(x-3y)(x-y).其中x²+9y
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
(1)已知x+y=6,x²-y²=5,求x-y的值(2)若x+y=3,x²+y²
(1)(2x+y-5)(2x-y+5) (2)(x+y)(x-y)-(x-y)²
[(x²+y²)-(x-y)²+2y(x-y)]÷1/2
已知x-y=1,y≠0,求{(x+2y)²+(2x+y)(x+4y)-3(x+y)(x-y)}÷y的值.
【(X²+Y²)-(X-Y)²+2Y(X-Y)】/4Y=1,求4X/4X²-Y&
化简 (x+y)(x²-xy+y²) ; 3(2x-1)(x+6)-5(x-3)(x+6)
计算4(x+y)^5(x-y)^4÷[2(x+y)³*(y-x)²]
因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y
1/2 x²y·( )=2x³y-x²y²