a^2+2a+b^2-6b+10=0
若a,b满足|a+5b-2|+(a+b-6)²=0,求代数式(a-3b)(a+2b)-(a+5b)(a+3b)
已知a*a+b*b-2a+4b+5=0,求2(a+b)(a-b)+(a-b)(a-b)-(6a*a*b-2a*b*b)/
a*a+b*b-2a+6b+10=0求a的2004次方+1/b的值
a²+2a+b²-6b+10=0,求a²-b²
a²+2a+b²-6b+10=0,求a、b
若a²+b²-2a+6b+10=0,求a+b
{1,a,b/a}={0,a^2,a+b}
化简求值(a-b)/(a+b)+(a+b)/(a-b)-(2a*a-2b*b)/(a*a+b*b)其中a=-2,b=0.
已知3a*a+ab-2b*b=0(a不等于0,b不等于0),求a/b-b/a-(a*a+b*b)/ab的值.
已知2a-b+1的绝对值+(3a+3/2b)^=0,求(b^/a+b)÷{[(b/a-b)+1][a-(a^/a+b)]
若a/b=2 则a*a-ab+b*b/a*a+b*b等于?
已知a+2b=0,求a*a+2ab-b*b/2a*a+ab+b*b