如何证明X^3+Y^3+Z^3-3XYZ>=0
证明x三次方+y三次方+z三次方>=3xyz
设X+Y+Z=0求X^3+X^2Z-XYZ+Y^2Z+Y^3的值
已知xyz满足|3x-2y+z|+|2x+y+2z|=0(xyz不等于o)求x+y除以z
先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2
x+y+z=xyz,x^2=yz,xyz不等于0,证x^3大于等于3
方程组:x-2y+4z=0,2x+3y-3z=0...xyz不等于0,求(2x+y-z)\(2x-y+z)
已知方程组4x-y+3z=0 2x+y+6z=0且xyz不等于0,则x/y+y/z+z/x是多少
已知4x-3y+z=0,x+2y-8z=0,xyz不等于0,求x+y-z/x-y+2z的值
x:y:z=2:3:4且x+y+z=18求xyz
已知x+y+z=0,求多项式x^3+x^2z-xyz+y^3的值
设函数z=z(x,y)由方程x^2+y^3-xyz^1=0确定,求z/x,z/y
已知有理数xyz 满足|x-z-2|+(3x-6y-7)的二次方+|3y+3z-4|=0 ,求xyz的值.