√(a²-3a+1)+b²+2a+1=0
已知|3a+3/2b|+(2a-b+1)²=0,求b²/a+b÷(a/a+b-1)(a-a²
已知|2a-b+1|+(3a+3/2b²=0,求b²/(a+b)÷[﹙a/(a-b)-1﹚﹙a-a&
若(a+1)²+/b-3/=0,求(a+2b)²-(2a+b)(a-b)-2(a-b)(a+b)的值
已知A=4a²-3a,B=2a²+a-1,求A-2(A-B)
化简 (a+b)²+2a(a-1/2b)-3(a-b)(a+b)
a(a-2b)+2(a+b)(a-b)+(a+b)²,其中a=-½,b=1
若√a²-3a+1 +b²+2b+1=0,求3a²-6a+1/a²-(-b)
若√(a²+3a+1)+b²+2b+1=0 求:1.2a²-6a+6b的立方根.2.a
已知(2a-b)²+│3a+b+5│=0,求代数式1-(a-b/a+2b)÷(a²-b²/
{1,a,b/a}={0,a^2,a+b}
已知|2a-b+1|+(3a+3/2b)^2=0求b^2/a+b/{(a/a-b-1)(a-a^2/a+b)}
已知|2a-b+1|+(3a+3/2b)^2=0求[b^2/a+b]/[(a/a-b-1)][(a-a^2/a-b)}