求证:log2(π)+log5(π)>2
2log5(25)-3log2(64)=?
(log3^4+log5^2)(log2^9+log2^根号3)
log2/log5等于多少
log2^25*log3^2倍根号2*log5^9=
log2^5*log3^2倍根号2*log5^9=
高一数学(log5)^2+log2·log50
(log2^5+log4^0.2)(log5^2+log25^0.25)化简
(log2)和(log3)变成(log5)
log2(5)*log5(8)化简
log的计算 :log2(20)-log4(25)= log3(2)×log2(5)×log5(3)=?log2[log
数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(
求下列各式的值 1)log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4)log3