find the first derivative of p(x)=ax2 + bx + c and use it to

来源：学生作业帮编辑：作业帮分类：英语作业时间：2024/05/14 07:12:45

find the first derivative of p(x)=ax2 + bx + c and use it to show that the vertex of the parabola is located at (-b/2a,-b2+4ac/4a).HINT:the tangent line is horizontal at the vertex of the parabola.Also,remember that the y-coordinate of a point on the parabola,and in particular of the vertex,is found by evaluating the quadratic polynomial/quadratic equation at the given x value.

p(x)=ax2 + bx + c
the first derivative is 2ax +

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