怎么化简cos(2x-π/3)-sin(2x-π/3),
Sin(x+π/3)+2Sin(x-π/3)-根号3乘以Cos(2π/3 -x ) 化简化简
已知函数f(x)=cos(2x-π/3)+sin^2 x-cos^2 x
已知函数f(x)=cos(2x-π\3)+sin²x-cos²x
已知函数f(x)=cos(2x-π/3)+2sin(x-π/4)sin(x+π/2) 化简为sin的形式
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π
已知函数f(x)= [sin(2π-x)sin(π+x)cos(-x-π)] /[2cos(π-x)sin(3π-x)]
sin(x+π/3)+2sin(x-π/3)-根号3cos(2π/3-x)
求化简数学公式哦[3sin^2(x/2)+cos^2(x/2)-4sin(x/2)cos(x/2)]/tan(π+x)化
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
已知cos(π/2+x)=sin(x-π/2) 求sin^3(π-x)+cos(x+π)/5cos(5π/2-x)+3s
三角函数已知P(-4,3) 求(cos((π/2)+x)sin(-π-x))/(cos((11π/2)-x)sin((9