2log^(x^2) = 3{2^(1+log x)} + 16

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/17 23:55:52

2log^(x^2) = 3{2^(1+log x)} + 16
2log^(x^2) = 3{2^(1+log x)} + 16

2^(log(x^2)) = 3( 2^(1+log(x)) ) +16
2^(2log(x)) = 3( 2^(1+log(x)) ) +16
[2^log(x)]^2 - 6(2^log(x)) -16=0
(2^log(x) -8)(2^log(x)+2) =0
2^log(x) =8 or 2^log(x) = -2 ( rej)
2^log(x) =8
2^log(x) =2^3
log(x) =3
x = 10^3 = 1000

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