(x+2y)(x-2y)*(x²-4y²)=
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
(x-2y)²+(2x-4y)(x+y)+(x+y)²
(2x-y)²-4(x-y)(x+2y)
化简:(2x-y)²-4(x-y)(x+y)
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
(x-2y)(x²-4y²)(x+2y)=什么?
[(y-2x)(-2x-y)-4(x-2y)²]*2y,其中x=1,y=2
求因式分解(x-y)²-2(x-y)³和(x+y)(x-y)-x(x-y)
(3x-y)²-2x(4x-5y)-(x+2y)²
【(2x+y)²-y(y+4x)-8x】÷2x,其中x=100
已知2x-y=10,求代数式[(x²+y²)-(x-y)²+2y(x-y)]÷4y的值?