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8x^3y^3-1/125 4a^2+b^2+c^2-4ab+4ac-2bc 5X^2-15x+2xy-6y a^2(x

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8x^3y^3-1/125 4a^2+b^2+c^2-4ab+4ac-2bc 5X^2-15x+2xy-6y a^2(x+y)^3-a^2b^3
还有几个
7(a+b)^2-5(a+b)-2
6x^2-7x-3
x^3+2x^2+2x+1
2X^2-3x-1
x^2+4x-1
8x^3y^3-1/125
=(2xy)^3-(1/5)^3
=(2xy-1/5)(4x^2y^2+2xy/5+1/25)
4a^2+b^2+c^2-4ab+4ac-2bc
=(2a-b)^2+2c(2a-b)+c^2
=(2a-b+c)^2
( 5X^2-15x+2xy-6y
=x(5x+2y)-3(5x+2y)
=(5x+2y)(x-3)
a^2(x+y)^3-a^2b^3
=a^2[(x+y)^3-b^3]
=a^2(x+y-b)[(x+y)^2+b(x+y)+b^2]
=a^2(x+y-b)(x^2+2xy+y^2+bx+by+b^2)
希望能帮到你,祝学习进步O(∩_∩)O
再问: 还有几个 帮帮忙 7(a+b)^2-5(a+b)-2 6x^2-7x-3 x^3+2x^2+2x+1 2X^2-3x-1 x^2+4x-1 16-8xy-16x^2-y^2
再答: 7(a+b)^2-5(a+b)-2=[7(a+b)+2][(a+b)-1]=(7a+7b+2)(a+b-1) 6x^2-7x-3=(3x+1)(2x-3) x^3+2x^2+2x+1=(x^3+x^2)+(x^2+2x+1)=x^2(x+1)+(x+1)^2=(x+1)(x^2+x+1) 2X^2-3x-1 (在有理数范围内不能分解因式) =2(x^2-3x/2-1/2)=2(x^2-3x/2+9/16-17/16) =2[(x-3/4)^2-(√17/4)^2]=2(x-3/4+√17/4)(x-3/4-√17/4) x^2+4x-1 (在有理数范围内不能分解因式) =x^2+4x+4-5 =(x+2)^2-(√5)^2 =(x+2+√5)(x+2-√5) 16-8xy-16x^2-y^2 =16-(16x^2+8xy+y^2) =4^2-(4x+y)^2 =(4+4x+y)(4-4x-y) 希望能帮到你,祝学习进步O(∩_∩)O