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计算(x*x+4x+5)/(x+2)-(x*x+6x+10)/(x+3)+1
分式混合计算(x+1/x^2-x - x/x^2-2x+1)*x
如何计算 (x+1)(x+2)(x+3)(x+4)
计算:(x+1)(x-2)(x-3)(x-6)
计算(X-1)(X-2)(X-3)(X-4)
计算x/(x^2-1) + (x^-x+1)/(x^3-x^2+x-1)+(x^2+x+1)/(x^3+x^2+x+1)
计算:(1+1/x)·x²-2x+1/x²-1;(x²/x-1-2x/1-x)÷x/x-1
计算:(1)(2x/x+2)的平方×x+2/x(x-2)-(1/x-2-1/x+2)
x^2-1/x^2+4x+4÷(x+1)×x^2+3x+2/x-1计算
计算:[(x²-2x+1)/(x²-1)]÷[(x-1)(x²+x)]-x
计算 已知x是15的平方根,求代数式x(x+1)^2-x(x^2+x)-x-7