sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan8
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/21 08:57:22
sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855°
sin(-1200°)=-sin(3*360° +120° )=-sin120°=-1/2
cos1290°=cos(4*360°-150°)=cos150°=-√3/2
cos(-120)°=cos120°=-1/2
cos(-1020)°=cos1020°=cos(3*360°-60°)=1/2
sin(-1050°)=sin(3*360°-30°)=-sin30°=-1/2
tan855°=tan135°=-1
sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855°
=-1/2-(-√3/2)-1/2+1/2-(-1/2)+(-1)=(√3-2)/2
cos1290°=cos(4*360°-150°)=cos150°=-√3/2
cos(-120)°=cos120°=-1/2
cos(-1020)°=cos1020°=cos(3*360°-60°)=1/2
sin(-1050°)=sin(3*360°-30°)=-sin30°=-1/2
tan855°=tan135°=-1
sin(-1200°)-cos1290°+cos(-120)°+cos(-1020)°-sin(-1050°)+tan855°
=-1/2-(-√3/2)-1/2+1/2-(-1/2)+(-1)=(√3-2)/2
sin(-1200°).cos1209°+cos(-1020°)-sin(-1050°)+tan855°
计算:sin(-1200°)·cos1230°+cos(-1020°)sin(-1050°)+tan1305°
(cos 45°-sin 30°)/(cos 45°+sin 30°)
Cos(180°+α)*sin(α+360°)/sin(-α-180°)*cos(-180°-α)
sin(x+105°)cos(x-15°)-cos(x+105°)sin求化简
sin平方120°+cos180°+tan45°-cos平方(-330°)+sin(-210°)
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cos tan sin 30° 45° 60°是多少
cos平方 48°+sin平方48°=
sin²15°-cos²15°=
cos²15°-sin²15°=
化解cos(45°-a)-sin(45°+a)