y=(x/128000-3x/80+8)*100/x,求导

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/16 20:35:31

y=(x/128000-3x/80+8)*100/x,求导
y=(x/128000-3x/80+8)*100/x,用导数求出极限…要详细步骤……

y=(x^3/128000-3x/80+8)*100/x=(x^3/128000-3x/80+8)*100x^(-1) y'=[(x^3/128000-3x/80+8)*100x^(-1)]' =(x^3/128000-3x/80+8)'*100x^(-1)+(x^3/128000-3x/80+8)*[100x^(-1)]' =(3x^2/128000-3/80)*100x^(-1)+(x^3/128000-3x/80+8)*100*(-1)x^(-2) =(3x^2/128000-3/80)*100x^(-1)-(x^3/128000-3x/80+8)*100x^(-2) =[(3x^3/128000-3x/80)-(x^3/128000-3x/80+8)]*100x^(-2) =100(x^3/64000-8)*x^(-2) 如有不妥请回复.

y=2x+8/x求导 y=3^-x*x^2,求导求导.y=x ln^3x y=x+x^x求导 y=x^x（x>0)求导 y=(x^2-3x+3)/√x求导. y=log10(x^3+2x^2+x) 求导求导:Y=(3X^4-1)^100 求y’ 1.y=e^(4xsin2x) 求导 2.x^3(x+y)=y^2(2x-y)求导 3.e^(x/y)=2x-y求导 x^3y+y^3-2x=0求导, 求导 y=3的3x次方求导 y=x( 3lnx + 1 ) 求导