Int x=2 (X>5)?x:2/x

int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少,为什么 void f( int y,int *x) {y=y+*x; *x=*x+y;} main( ) { int x=2,y int x=2; x*7.2/x+1 等于几 int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 结果是多少?x=( main(){ int x=5; while(x int x=5; int y=2+(x+=x++,x+8,++x); printf("%d",y); 求程序的结果并解释 int x,y; x=13; y=5; {printf("%d",x%=(y/=2)); int fun(int x) { int y; if(x>1) y=fun(x-1)+2; else y=2; retu #include void f(int*x,int y) {*x=y+1;y=*x+2;} main() {int a= fun(int x,int *y) { int z; x-=2;(*y)++; z=x%(*y); return z; int x=20; int i=2; while(i x为int类型变量 执行 x+=x*=(x=2*3,x-2)后x=多少?