x²+2x-3 2x²-7x+6 3x²y²-10xy+7 -y²+2
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 00:01:41
x²+2x-3 2x²-7x+6 3x²y²-10xy+7 -y²+20y-96 用配方法把上述因式分解
x²+2x-3 =x²+2x+1-4=(x+1)^2-4 =(x+1-2)(x+1+2)=(x-1)(x+3)
3x²y²-10xy+7 =(9x²y²-30xy+25-4)/3=[(3xy-5)^2-4]/3=1/3*(3xy-7)(3xy-3)
-y²+20y-96=-(y²-20y+100-4)=-[(y-10)^2-4]=-(y-8)(y+12)
再问: 2x²-7x+6 这个呢?
再答: =(16x²-56x+49-1)/8=1/8*[(4x-7)^2-1]=1/8*(4x-6)(4x-8)
3x²y²-10xy+7 =(9x²y²-30xy+25-4)/3=[(3xy-5)^2-4]/3=1/3*(3xy-7)(3xy-3)
-y²+20y-96=-(y²-20y+100-4)=-[(y-10)^2-4]=-(y-8)(y+12)
再问: 2x²-7x+6 这个呢?
再答: =(16x²-56x+49-1)/8=1/8*[(4x-7)^2-1]=1/8*(4x-6)(4x-8)
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A=2x²-3xy+y²-x+2y,B=4x²-6xy+2y²+3x-y,若x=
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分解因式:x²+3xy+2y²+5x+7y+6