来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/13 10:17:28
运算放大器与受控源问题
如图,求转移电阻和转移电导
设电流并编号,见图
分析计算如下
i1=i=i3+i2
R1i1+R2i2=0
i2=-(R1/R2)i1
i3=i1-i2=(1+R1/R2)i1
u2=-R1i1-R3i3=-R1i1-R3(1+R1/R2)i1=-R1i-R3(1+R1/R2)i
u2=-[R1+R3(1+R1/R2)]i
转移电阻-[R1+R3(1+R1/R2)]
转移电导-1/[R1+R3(1+R1/R2)]