2xy/x^2-y^2+x/x+y,(a^2/a-2-4/a-2)X1/a^2+2a)Xa^2+2a,(1+3/x-1)
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/10 23:31:04
2xy/x^2-y^2+x/x+y,(a^2/a-2-4/a-2)X1/a^2+2a)Xa^2+2a,(1+3/x-1)÷x+2/x^2-1化简
解1题:
原式=2xy/(x²-y²)+x/(x+y)
=2xy/[(x+y)(x-y)]+[x(x-y)]/[(x+y)(x-y)]
=[2xy+x(x-y)]/[(x+y)(x-y)]
=(2xy+x²-xy)/[(x+y)(x-y)]
=(x²+xy)/[(x+y)(x-y)]
=[x(x+y)]/(x+y)(x-y)]
=x/(x-y)
解2题:
原式=[a²/(a-2)-4/(a-2)]×[1/(a²+2a)]×(a²+2a)
=[(a²-4)/(a-2)]
=[(a+2)(a-2)]/(a-2)
=a+2
解3题:
原式=[1+3/(x-1)]÷[(x+2)/(x²-1)]
=[(x-1+3)/(x-1)]×[(x²-1)/(x+2)]
=[(x+2)/(x-1)]×[(x+1)(x-1)/(x+2)]
=x+1
原式=2xy/(x²-y²)+x/(x+y)
=2xy/[(x+y)(x-y)]+[x(x-y)]/[(x+y)(x-y)]
=[2xy+x(x-y)]/[(x+y)(x-y)]
=(2xy+x²-xy)/[(x+y)(x-y)]
=(x²+xy)/[(x+y)(x-y)]
=[x(x+y)]/(x+y)(x-y)]
=x/(x-y)
解2题:
原式=[a²/(a-2)-4/(a-2)]×[1/(a²+2a)]×(a²+2a)
=[(a²-4)/(a-2)]
=[(a+2)(a-2)]/(a-2)
=a+2
解3题:
原式=[1+3/(x-1)]÷[(x+2)/(x²-1)]
=[(x-1+3)/(x-1)]×[(x²-1)/(x+2)]
=[(x+2)/(x-1)]×[(x+1)(x-1)/(x+2)]
=x+1
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