(6c^4d^2-c^3d^3)/(-2c^3d)=
2c+3d=95 3c+2d=80 c+d=( )
2c+3d=95 3c+2d=80 c+d=
2c+3d=95,3c+2d=80,c+d=?
已知ab互为相反数,c与d互为倒数,x=4(a-2)-(a-3b),y=c²d+d²-(d/c+c-
(6c^2-c^3d^3)除以(-2c^2d)
已知:a、b、c、d都是自然数,a ^6=b ^4,c ^3=d ^2,a-c=19 求:b-d的值
已知:a/b=c/d,求证:(2a+3b)/(a+b)=(2c+3d)/(c+d)
已知a/b=c/d,求证2a+3b/a+b=2c+3d/c+d
(a/(b+2c+3d))+(b/(c+2d+3a))+(c/d+2a+3b))+(d/(a+2b+3c))>=2/3
a,b,c,d>0 证(a/(b+2c+3d))+(b/(c+2d+3a))+(c/d+2a+3b))+(d/(a+2b
C语言 int a;int b; }d[3] ={{1,4},{2,5},{6,7}}; printf("%d\n",d
a.d.c都是有理数,那么2a-3d+c与它的相反数的差是()A4a-6d+2c B6d-4a+2c C4a+6d-2c