复数z=(2-i)/i则z的绝对值=?
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/06/01 15:44:28
复数z=(2-i)/i则z的绝对值=?
z=(2-i)/i
=i(2-i)/i²
=(2i-i²)/(-1)
=(2i+1)/(-1)
=-1-2i
|z|
=√[(-1)²+(-2)²]
=√5
再问: 那要是z=(2-i)^2/i该怎么求呢??
再答: z=(2-i)²/i =i(2-i)²/i² =i(4-4i+i²)/(-1) =i(4-1-4i)/(-1) =i(3-4i)/(-1) =(3i+4)/(-1) =-3i-4 |z| =√[(-3)²+(-4)²] =5 请点击左下角的“采纳为满意答案”,祝学习进步!
=i(2-i)/i²
=(2i-i²)/(-1)
=(2i+1)/(-1)
=-1-2i
|z|
=√[(-1)²+(-2)²]
=√5
再问: 那要是z=(2-i)^2/i该怎么求呢??
再答: z=(2-i)²/i =i(2-i)²/i² =i(4-4i+i²)/(-1) =i(4-1-4i)/(-1) =i(3-4i)/(-1) =(3i+4)/(-1) =-3i-4 |z| =√[(-3)²+(-4)²] =5 请点击左下角的“采纳为满意答案”,祝学习进步!
若复数z满足(z+i)(1+2i)=i求z的绝对值
设复数Z满足Z+Z的绝对值=2+i 那么Z等于多少
复数z满足 z+3i绝对值=1 z绝对值=2 求z
复数Z=1+i 求Z的绝对值
复数z=1+2i,则复数z-i/z+i的虚部是
如果复数z满足z+1-i的绝对值=2,那么z-2+i的绝对值的最大值是
已知i为虚数单位,复数z=6+8i,则复数z的模绝对值z=
复数z的共轭复数为-z,已知z=2i/1-i,则z×-z=?
z拔为复数z的共辄复数,z-z拔=2i,z的绝对值为根号5,求z
已知复数Z.=3+2i 复数z满足Z.*z=3z+Z.则复数z等于?
设复数z=a+i,绝对值z等于根号2,求复数z,和z+1分之z格玛
Z+|Z的共轭复数|=2+i .Z=?