计算:(1-1/a-1)-a²-4a+4/a²-a;(a/a-2-a/a+2)·4-a²/
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计算:(1-1/a-1)-a²-4a+4/a²-a;(a/a-2-a/a+2)·4-a²/a.
拜托了!!!急啊
拜托了!!!急啊
[1-1/(a-1)] -(a²-4a+4)/(a²-a)
=(a-1-1)/(a-1) - (a-2)²/[a(a-1)]
=[a(a-2)-(a-2)²]/[a(a-1)]
=[(a-a+2)(a-2)]/[a(a-1)]
=2(a-2)/[a(a-1)]
.
[a/(a-2) - a/(a+2)]· (4-a²)/a
=[a/(a-2)] · (4-a²)/a - [a/(a+2)]· (4-a²)/a
=-(a+2) - (2-a)
=-a-2-2+a
=-4
=(a-1-1)/(a-1) - (a-2)²/[a(a-1)]
=[a(a-2)-(a-2)²]/[a(a-1)]
=[(a-a+2)(a-2)]/[a(a-1)]
=2(a-2)/[a(a-1)]
.
[a/(a-2) - a/(a+2)]· (4-a²)/a
=[a/(a-2)] · (4-a²)/a - [a/(a+2)]· (4-a²)/a
=-(a+2) - (2-a)
=-a-2-2+a
=-4
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