an=2*n+1,bn=1/(an^2-1),求数列b前n项和Tn
设bn=(an+1/an)^2求数列bn的前n项和Tn
an=3*2^(n-1),设bn=n/an求数列bn的前n项和Tn
数列{an},a1=1,an=2-2Sn,求an,若bn=n*an,求{bn}的前n项和Tn
已知数列{an}前n项和Sn=n^2+n,令bn=1/anan+1,求数列{bn}的前n项和Tn
已知数列an=4n-2和bn=2/4^(n-1),设Cn=an/bn,求数列{Cn}的前n项和Tn
错位相减法,数列求和an=n+1,bn=an/2^n-1,求数列bn的前n项和Tn.一轮复习,
已知数列an的通项公式为an=2n-1,数列bn的前n项和为tn且满足tn=1- b
数列an,满足Sn=n^2+2n+1,设bn=an*2^n,求bn的前n项和Tn
已知数列bn满足bn=b^2n,其前n项和为Tn,求(1-bn)/Tn
已知数列an的前n项和为sn=2n^2+5n+1,数列bn的前n项和tn满足Tn=(3/2)bn-3/2 求数列an的通
(2)若数列{bn}满足bn=an log2 an+1,求数列{bn}的前n项和Tn
数列an的前n项和为Sn,Sn=2an-1,数列bn满足b1=2,bn+1=an+bn.求数列bn的前n项和Tn