sin25π÷6+cos25π÷3+tan(-25π÷4)是怎么计算的?
计算:sin25π/6+cos25π/4+tan(-25π/4)+sin(-26π/3)
sin25π/4+cos25π/3+tan(-25π/4)=
求值sin25π/6+cos25π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-
sin25/6pai+cos25/3pai+tan(-25/4pai)
1.化简sin25/12πsin11/6π-cos25/12πcos11/6π的值是
三角函数的计算题目cos25/3*π=tan(-15/4*π)
sin25π/6+cos10π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)=
sin25π6
1sin3分之4π乘以6分之cos25π乘以tan-4分之3π=
求sin25π/6+cos5π/3+tan(-25π/4)+sin(-7π/3)×cos(-13π/6)-sin(-5π
cos25πtdt (0~π/4)的微积分怎么求?
cos25π/3等于?请告诉我具体的方法,O(∩_∩)O谢谢