计算:(1)x+1/x-1/x,(2)a/b+1+2a/b+1-3a/b+1
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/24 12:39:22
计算:(1)x+1/x-1/x,(2)a/b+1+2a/b+1-3a/b+1
计算:(1)(x+1/x)-(1/x),(2)(a/b+1)+(2a/b+1)-(3a/b+1),(3)(1/2c²d)+(1/3cd²),(4)(3/2m-n)-(2m-n/(2m-n)²),(5)(a/a²-b²)-(1/a+b),(6)(a²/a-1)-(a-1)【每个分数的括号是为了区分开加减号】
计算:(1)(x+1/x)-(1/x),(2)(a/b+1)+(2a/b+1)-(3a/b+1),(3)(1/2c²d)+(1/3cd²),(4)(3/2m-n)-(2m-n/(2m-n)²),(5)(a/a²-b²)-(1/a+b),(6)(a²/a-1)-(a-1)【每个分数的括号是为了区分开加减号】
(1)( x+1-1)/x = 1 (2) (a + 2a - 3a)/(b+1) = 0 (3) (3cd² + 2c²d)/6c^3d^3
(4) [3/(2m-n)] - [1/(2m-n) ]= 2/(2m-n)
(5)[a/(a²-b²)] -(a-b)/(a²-b²) = b/(a²-b²)
(6)[a²/(a-1)] - [(a-1)x(a-1)]/(a-1)
=(a² - a² +2a - 1)/(a-1)
=(2a - 1)/ (a-1)
(4) [3/(2m-n)] - [1/(2m-n) ]= 2/(2m-n)
(5)[a/(a²-b²)] -(a-b)/(a²-b²) = b/(a²-b²)
(6)[a²/(a-1)] - [(a-1)x(a-1)]/(a-1)
=(a² - a² +2a - 1)/(a-1)
=(2a - 1)/ (a-1)
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