|2a-1|+(3b+2)²=0,求a²-3b²÷(a+b)这题怎么算啊?
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|2a-1|+(3b+2)²=0,求a²-3b²÷(a+b)这题怎么算啊?
根据题意,得:
2a-1=0且3b+2=0
得:a=1/2、b=-2/3,则:
a²-3b²÷(a+b)
=(1/2)²-3×(-2/3)²÷[(1/2)+(-2/3)]
=(1/4)-3×(4/9)÷[-(1/6)]
=(1/4)-(4/3)×[-6]
=(1/4)+8
=33/4
再问: 对不起啊,忘记了个东西了是(a²-3b²)÷(a+b),忘打括号了,能再解答一下吗?专家?
再答: ²³²³ 根据题意,得: 2a-1=0且3b+2=0 得:a=1/2、b=-2/3,则: (a²-3b²)÷(a+b) =[(1/2)²-3×(-2/3)²]÷[(1/2)+(-2/3)] =[(1/4)-3×(4/9)]÷[-(1/6)] =[(1/4)-(4/3)]×[-6] =[-13/12]×[-6] =13/2
2a-1=0且3b+2=0
得:a=1/2、b=-2/3,则:
a²-3b²÷(a+b)
=(1/2)²-3×(-2/3)²÷[(1/2)+(-2/3)]
=(1/4)-3×(4/9)÷[-(1/6)]
=(1/4)-(4/3)×[-6]
=(1/4)+8
=33/4
再问: 对不起啊,忘记了个东西了是(a²-3b²)÷(a+b),忘打括号了,能再解答一下吗?专家?
再答: ²³²³ 根据题意,得: 2a-1=0且3b+2=0 得:a=1/2、b=-2/3,则: (a²-3b²)÷(a+b) =[(1/2)²-3×(-2/3)²]÷[(1/2)+(-2/3)] =[(1/4)-3×(4/9)]÷[-(1/6)] =[(1/4)-(4/3)]×[-6] =[-13/12]×[-6] =13/2
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