设函数f(x)在点x=2处可导,且f'(2)=2,则limh→0 f(2+h)-f(2)/2h =( ) A1/2 B1
设函数f(x)在点x0处可导,且f'(x0)=2,则lim(h→0)[f(x0-h/2)-f(x0)]/h等于多少
设函数f(x)在x=a处的导数为f'(a),求limh→0 f^2(a)-f^2(a-h)/h 答案为2f(a)f'(a
设函数f(x)在x=1处可导,且f'(1)=2,则[lim(h→0)f(1-h)-f(1)]/h等于
设f(x)在x=2处可导,且f'(2)=1,则lim h→0 [ f(2+h)-f(2-h)]/h等于多少,
设函数f(x)在x=x0处可导,则lim(h>0)[f(x0)-f(x0-2h)]/h
设f(x)在x=x0的邻近有连续的二阶导数,证明;limh→0f(x0+h)+f(x0-h)-2f(x0)/h²
设函数f(x)在x=a处可导,且lim[f(a+5h)]-f(a-5h)]/2h=1,则f'(a)=
设函数f(x)在x=x0处可导,则limh→0f(x0+h)−f(x0)h( )
设f(x)为可导函数,且lim(h→0) f(3)-f(3+h)/2h=5,则f'(3)等于?
若函数f(x)在点x=a处可导,则lim(h→0)[f(a+4h)-f(a-2h)]/3h=?
设函数f(x)在点x处可导,试求h→0 lim f(x+h)-f(x-h)/2h的值
设 函数 f(x)在x=2处可导,且f(2)的导数=1求: lim f(2+h)—f(2—h)/2h h→0