3^1+x=8+3^1-x,求x用log
(高一)若x满足2(log(1/2)x)^2-14log(4)x+3≤0,求f(x)=[log(2)(x/2)]*{lo
1/log(2)x+1/log(3)x+1/log(4)x=1,x=?
已知log以3为底(x-1)=log以9为底(x+5),求x的值
求函数 y=LOg(x-1) (-x的平方+2X+3)的定义域
求此函数的定义域f(x)=log(x-1)(3-x)
已知x满足不等式log (1/2) x^2≥log(1/2) (3x-2).求函数f(x)=[log2 x/4]×(lo
已知函数f(x)=log.(1-x)+log.(x+3)(0
lg(7*2^x+8)>=log(√10) 2^x,求函数f(x)=log(1/2)x*log(1/2)x/4的最小值
log(x-1) (x^2-8x+7)=1,求x的值
2 log(3x)= log 4 +log(6-x)怎么求...急
化简:1/log(3)x 1/log(4)x 1/log(5)x=……(答案是1/log(60)x
log(2x)+log(3y)-log(2z) 怎么化简? log3(x^2-2x-6)=2 log(3x+6)=1+l