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3x+3y=-3 x(x+y)(x+2y)=-8 求x,y

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3x+3y=-3 x(x+y)(x+2y)=-8 求x,y
3x+3y=-3 x(x+y)(x+2y)=8
∵ 3 x + 3 y = - 3
∴ x + y = - 1
∴ y = - 1 - x
∴ x(x + y)(x + 2 y)= 8 【把 y = - 1 - x 代入】
x(x - 1 - x)(x - 2 - 2 x)= 8
x ·(- 1)(- 2 - x)= 8
x(x + 2)= 8
x ² + 2 x = 8
x ² + 2 x + 1 = 9
(x + 1)²= 9
x + 1 = ± 3
x = ± 3 - 1
x1 = 3 - 1 = 2
x2 = - 3 - 1 = - 4
①当 x = 2 时,则 y = - 1 - 2 = - 3
② 当 x = - 4 时,则 y = - 1 -(- 4)= - 1 + 4 = 3