(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y))^2010=x/
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/11 20:09:39
(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y))^2010=x/(x-y)=1/(1-y/x)=1/(1-9/10
x/(x-y)=1/(1-y/x我只是不要明白这不是怎样算出来的请详细讲解,
x/(x-y)=1/(1-y/x我只是不要明白这不是怎样算出来的请详细讲解,
(1-y/x)^2009*(x/(y-x))^2010
=[(x-y)/x]^2009*[x/(x-y)]^2010
=[x^(2010-2009)]/[(x-y)^(2010-2009)]
=x/(x-y)
分子分母同时除以x
=(x/x)/[(x-y)/x] [(x-y)/x]=x/x-y/x=1-y/x
=1/(1-y/x)
=1/(9-10)
=-1
=[(x-y)/x]^2009*[x/(x-y)]^2010
=[x^(2010-2009)]/[(x-y)^(2010-2009)]
=x/(x-y)
分子分母同时除以x
=(x/x)/[(x-y)/x] [(x-y)/x]=x/x-y/x=1-y/x
=1/(1-y/x)
=1/(9-10)
=-1
先化简,再求值 (1)[(x-y)的平方+(x+y)(x-y)]÷2x 其中X=2010,y=2009 (2)y(x+y
{(x,y) |x|+|y|
x>y?x:y
当x-y/x+y=2009/2010时,求代数式2009(x+y)/x-y+4020(x-y)/x+y的值.
1、x(x-y)(x+y)-x(x+y)^2
y=(x^2+x)/(x+1)
xy=2010,x+y=2009,求x,y
已知(2011+y-x)(x-y-2009)=-2010,求(2011+y-x)²+(2009+y-x)&su
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
二元函数f(x,y)=x+y/x-y,求f(y/x,x/y)
(1)(x^2/x)-y-x-y
先化简再求值(x-y)(x+y)-(x-2y) 的完全平方+x(3x-5y)-(x-y)(x-2y),其中x=1/2 y