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(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y))^2010=x/

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/11 20:09:39
(1-y/x)^2009*(x/(y-x))^2010=((x-y)/x)^2009*(x/(x-y))^2010=x/(x-y)=1/(1-y/x)=1/(1-9/10
x/(x-y)=1/(1-y/x我只是不要明白这不是怎样算出来的请详细讲解,
(1-y/x)^2009*(x/(y-x))^2010
=[(x-y)/x]^2009*[x/(x-y)]^2010
=[x^(2010-2009)]/[(x-y)^(2010-2009)]
=x/(x-y)
分子分母同时除以x
=(x/x)/[(x-y)/x] [(x-y)/x]=x/x-y/x=1-y/x
=1/(1-y/x)
=1/(9-10)
=-1