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ansys出现警告说旋转角度超过180度

来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/12 17:10:37
ansys出现警告说旋转角度超过180度
/filname,LeaderAxis6,1
/Title,'A design of a leaderaxis'
/prep7
et,1,solid92
mptemp,
MPTEMP,1,0
mpdata,ex,1,2e11
mpdata,prxy,1,0.3
cylind,1,0,m_d4/2,0,m_l4,0,360
CYLiND,2,0,m_d3/2,m_l4,m_l4+m_l3,0,360
CYLIND,3,0,m_d2/2,m_l4+m_l3,m_l4+m_l3+m_l2,0,360
CYLIND,4,0,m_d1/2,m_l4+m_l3+m_l2,m_l4+m_l3+m_l2+m_l1,0,360
CYLIND,5,0,m_d5/2,0,-m_l5,0,360
CYLIND,6,0,m_d6/2,-m_l5,-(m_l5+m_l6),0,360
WPOFFS,m_d1/2,-(m_l1/2+m_l2+m_l3)
wprota,-90
csys,4
K,49,m_jw1/2,m_jl1/2-m_jw1/2
K,50,-m_jw1/2,m_jl1/2-m_jw1/2
K,51,m_jl1/2
K,52,-m_jw1/2,-(m_jl1/2-m_jw1/2)
K,53,m_jw1/2,-(m_jl1/2-m_jw1/2)
K,54,-m_jl1/2
lstr,50,52
lstr,49,53
larc,49,50,51
larc,53,52,54
怎么运行到csys 4前都正常,在后面麻烦看下有什么问题,每次运行都出现错误.这个是在轴上开键槽的问题
怎么不见你的定义的变量名称呢,这样也没法看你的命令流啊,不知道你定义的关键点坐标是怎样的,不过,你后面要定义弧线,需要保证弧线是四分之一的圆,或者是二分之一的圆的长度才行,不能直接画出一个圆
再问: m_d1=65 m_d2=70 m_d3=75 m_d4=83 m_d5=70 m_d6=65 m_l1=107 m_l2=115 m_l3=78 m_l4=530 m_l5=60 m_l6=85 m_jh1=9 m_jl1=80 m_jw1=14 m_jh2=12 m_jl2=60 m_jw2=20 m_jh3=11 m_jl3=82 m_jw3=18这是参数,是键槽的圆弧,180度,但是总是提示旋转超过180度,我试着用路径来了下也是画圆弧这里出了问题,是不是工作平面设置有问题。谢谢
再答: LARC,49,50,51,10, 这里定义半径为10,你这样试下,你的命令是不是没有用对呢 你看下这个命令的英文说明,与你的坐标系没有什么大的关系 LARC LARC, P1, P2, PC, RAD Defines a circular arc. PREP7: Lines MP ME ST PR PRN FL EM EH DY PP EME MFS P1 Keypoint at one end of circular arc line. If P1 = P, graphical picking is enabled and all remaining command fields are ignored (valid only in the GUI). P2 Keypoint at other end of circular arc line. PC Keypoint defining plane of arc and center of curvature side (with positive radius). Must not lie along the straight line from P1 to P2. PC need not be at the center of curvature. RAD Radius of curvature of the arc. If negative, assume center of curvature side is opposite to that defined by PC. If RAD is blank, RAD will be calculated from a curve fit through P1, PC, and P2.