lim(x→0)[ln(1+x)]/x=lim(x→0)[ln(1+x)]^(1/x)

lim(x→0)ln(1-2x)/x 求极限lim Ln(1+x) /x > .< x→0 对数函数的极限 lim(x→0) [ln(1+x)-ln(1-x)]/x 已知f(x)=ln(1+x) 求lim(x→0) f(x)/x lim(x→0)(cosx)^(1/ln(1+x^2)) lim(x→0)ln（x^2+1）等于 lim(x→0)(ln(1+x^2)/(sec-cosx)) lim(x->0)ln(1+2x)/e^x-1 x趋向0 lim [ ln (1-x) / (e ^ x-1 ) ] lim(x趋向0)ln(1+sin x)/x^2 lim(x趋于0)[ln(1+2x)]/x lim(x->0)(ln(1+x))/x 不用导数