作业帮美帝化学题.关于气体反应的.
来源：学生作业帮 编辑：作业帮 分类：英语作业 时间：2024/05/17 07:03:43
美帝化学题.关于气体反应的.
21.(6 pts) Consider the following reaction:4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g)
When 3.0 L of ammonia gas reacts with 6.0 L of oxygen gas,how many liters of gas total will there be in
the container?Assume that the reaction goes to completion and that all volumes of gases are measured at
the same temperature and pressure.
大意就是根据以上反映如果有3LNH3 和6L O2互相反应,最后容器内气体的体积共会有多少.我知道绝对不会很难但还是智商捉急.求大神拯救.
21.(6 pts) Consider the following reaction:4 NH3(g) + 5 O2(g) = 4 NO(g) + 6 H2O(g)
When 3.0 L of ammonia gas reacts with 6.0 L of oxygen gas,how many liters of gas total will there be in
the container?Assume that the reaction goes to completion and that all volumes of gases are measured at
the same temperature and pressure.
大意就是根据以上反映如果有3LNH3 和6L O2互相反应,最后容器内气体的体积共会有多少.我知道绝对不会很难但还是智商捉急.求大神拯救.
首先判断氨气和氧气哪个过量.
反应方程式中氨气和氧气的系数比为4:5.加入的氨气和氧气的物质的量之比为1:2.
5L氧气反应需要消耗4L氨气,但是氮气只有3L.
氧气过量,氨气完全参与反应.
3L氨气消耗氧气的体积为
3L*5/4=3.75L
剩余氧气的体积=6L-3.75L=2.25
L.
生成的气体体积为
3L+3L*6/4=7.5L
反应后的总体积=2.25L+7.5L=9.75L
反应方程式中氨气和氧气的系数比为4:5.加入的氨气和氧气的物质的量之比为1:2.
5L氧气反应需要消耗4L氨气,但是氮气只有3L.
氧气过量,氨气完全参与反应.
3L氨气消耗氧气的体积为
3L*5/4=3.75L
剩余氧气的体积=6L-3.75L=2.25
L.
生成的气体体积为
3L+3L*6/4=7.5L
反应后的总体积=2.25L+7.5L=9.75L