(x^2 +4x+4-y^2)除以(x+y+2)
{(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y
已知2x-y除以x+y等于2,求代数式(4x-2y除以x+y)-(4x+4y除以2x-y)的值
【(x-y)^2+(x+y)(x-y)】除以 2x
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
y^2-x^2\5x^2-4yx除以x+y\5x-4y
[(5x+2y)(3x+2y)+(x+2y)(x-2y)]除以4x
[(3x+2y)(3x-2y)-(x+2y)(5x-2y)]除以4x
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
2x^4+4x^2y^2+2y^4除以(x²+y²)
(-2X^2/Y)^2*(-2Y^2/3X)^2除以(2Y/X)^4
已知2x-y/x+3y=2,求代数式4x-2y/x+3y减4x+12y除以2x-y
x-2y分之x-y除以x^2-4xy+4y^2分之x^2-y^2