cos(2π-x)=cosx吗
sin(x+1/2π)=cosx?还是cos-x
已知函数fx=[cosx+cos(π/2-x)][cosx+sin(π+x)]
已知函数f(x)=cos(2x-π/3)+(cosx+sinx)(cosx-sinx)
根号2cos(x-π/2)怎么=sinx+cosx
cosx+根号3sinx=2cos(x-π/3)
1.化简f(x)=cosx(asinx-cosx)+cos(π/2-x)cos(π/2-x).2.化简f(x)=4cos
化简2sinx*cosx*cos(2π-x)+cos(π+2x)*cosx*tanx
sinx+cosx/sinx-cosx=2 求sinx/cos^3x +cosx/sin^3x
为什么cos(-x)=cosx.
化简f(x)=sin(x/2+π/12)乘以cos(x/2+π/12)-cosx/2乘以cosx/2
f(x)=2cos*sin(x+π/3)-^3sin^2x+sinx*cosx
已知函数f(x)=cosx+cos(x+π/2),x∈R