求x=1+cos(t)和y=sin(t) 面积
求由摆线x=a(t-sin t),y=a(1-cos t)及x轴所围成的图形的面积(0
设函数y=y(x)由参数方程x=cos t,y=sin t - t cos t确定,求dy/dx
设x=e'sin t,y=e'cos t,求dy/dx.
求导:x=cos^4*t,y=sin^4*t,求dy/dx
x=2sin(t),y=cos(t+pie),求dy/dx,和d^2y/dx^2,在点(0,-1)
如何x(t)=cos(t)+asin(t) y(t)=sin(t)+bcos(t) expressing x(t) in
1.利用plot函数在区间[0,2π]同时绘制x=sin(t)和y=cos(t),z=sin(t)+cos(t)的图形.
利用plot函数在区间[0,2π]同时绘制x=sin(t)和y=cos(t),z=sin(t)+cos(t)的图形.要求
t=0:pi/100:10*pi; x=2*(cos(t)+t*sin(t)); y=2*(sin(t)-t*cos(t
已知 x = e^t * cos t y = e^t *sin t 求当t= π/3时dy/dx的值
matlab中t=linspace(0,2*pi,100);x=[t;t]';y=[sin(t);cos(t)]';pl
matlaB函数问题t = -pi:0.01:pi;x=cos(t)-sin(3*t);y=sin(t)+cos(t);