作业帮(3x+9)(6x+8) (3x+7y)(3x-7y) (1/3a^2b^2)(-15a^2b^2) (3mn+1)(3
来源：学生作业帮 编辑：作业帮 分类：数学作业 时间：2024/05/09 02:52:25
(3x+9)(6x+8) (3x+7y)(3x-7y) (1/3a^2b^2)(-15a^2b^2) (3mn+1)(3mn-1)-8m^2n^2 (x+2)^2-(x+1)(x-1)
(x+y+z)(x+y-z)
(1)(3x+9)(6x+8) (2)(3x+7y)(3x-7y) (3) (1/3a^2b^2)(-15a^2b^2) (4)(3mn+1)(3mn-1)-8m^2n^2 (5) (x+2)^2-(x+1)(x-1) （6)（x+y+z)（x+y-z） 上面的有点不清晰这才是
(x+y+z)(x+y-z)
(1)(3x+9)(6x+8) (2)(3x+7y)(3x-7y) (3) (1/3a^2b^2)(-15a^2b^2) (4)(3mn+1)(3mn-1)-8m^2n^2 (5) (x+2)^2-(x+1)(x-1) （6)（x+y+z)（x+y-z） 上面的有点不清晰这才是
(1)(3x+9)(6x+8)
=18x^2+24x+54x+72
=18x^2+78x+72
(2)(3x+7y)(3x-7y)
=9x^2-49y^2
(3) (1/3a^2b^2)(-15a^2b^2)
=(-15a^2b^2)/(3a^2b^2)
=-15/3
=-5
(4)(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
(5) (x+2)^2-(x+1)(x-1)
=x^2+4x+4-(x^2-1)
=x^2+4x+4-x^2+1
=4x+5
（6)（x+y+z)（x+y-z）
=[(x+y)+z] [(x+y)-z]
=(x+y)^2-z^2
=x^2+y^2+2xy-z^2
=x^2+y^2-z^2+2xy
=18x^2+24x+54x+72
=18x^2+78x+72
(2)(3x+7y)(3x-7y)
=9x^2-49y^2
(3) (1/3a^2b^2)(-15a^2b^2)
=(-15a^2b^2)/(3a^2b^2)
=-15/3
=-5
(4)(3mn+1)(3mn-1)-8m^2n^2
=9m^2n^2-1-8m^2n^2
=m^2n^2-1
(5) (x+2)^2-(x+1)(x-1)
=x^2+4x+4-(x^2-1)
=x^2+4x+4-x^2+1
=4x+5
（6)（x+y+z)（x+y-z）
=[(x+y)+z] [(x+y)-z]
=(x+y)^2-z^2
=x^2+y^2+2xy-z^2
=x^2+y^2-z^2+2xy
因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(
已知:6x²-7xy-3y²+14x+y+a=(2x-3y+b)(3x+y+1)求a,b的值
(2x+y)(2x-3y)+x(2y+y) 2a(x-y)-4b(x-y)
1.已知集合A=｛（x,y)|y=2x+1｝,B=｛(x,y)|y=x+3｝,a∈A,b∈B,求a
因式分解 1)9x^4-25y^6 2)4x^2+(x+y)^2+4x(x+y) 3)(a+2b)^2-4ab-13b^
已知集合A=｛(x,y)｜(y-3)/(x-2)=a+1｝B=｛(x,y)｜(a^2-1)x+(a-1)y=15｝,当a
(3x-y)(3x+y)+y(x+y);(a+1/2b)(a-1/2b)-(3a-2b)(3a+2b)快点,
几道因式分解..4ab(a+b)^2-6a^2b(a+b)(x+y)^2(x-y)+(x+y)(x-y)^22a(a-3
计算：（1） （2x-3y)+(5x+4y) (2) (8a-7b)-(4a-5b)
已知集合A={（x,y)| (y-3)/ (x-1)=2,x,y∈R},B={（x,y)| 4x+ay=16,x,y∈
已知集合A=｛(x,y)|3x-7y=-5},B={(x,y)|2x+9y=40},求A∩B（用列举
1.设A={(x,y)/4x+y=6} B={(x,y)/3x+2y=7} 则A∩B等于多少