高等数学求偏导数这题怎么做: x z=ln tan----- y
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/17 13:38:41
高等数学求偏导数这题怎么做: x z=ln tan----- y
题目是z=ln tan x/y
希望能把这道题的步骤给我看
题目是z=ln tan x/y
希望能把这道题的步骤给我看
dz =[1/tan(x/y)]*sec^2(x/y) *[dx/y + (-x/y^2)dy]
dz/dx = 2 /[y *sin(2x/y)]
dz/dy= - 2x/[y^2*sin(2x/y)]
dz/dx =d (ln tan x/y)/dx
=(1/tan( x/y)) *d (tan x/y)/dx
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*dx/y
=2 /[y *sin(2x/y)]
dz/dy =d (ln tan x/y)/dy
=(1/tan( x/y)) *d (tan x/y)/dy
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*(-x/y^2)
= - 2x/[y^2*sin(2x/y)]
dz/dx = 2 /[y *sin(2x/y)]
dz/dy= - 2x/[y^2*sin(2x/y)]
dz/dx =d (ln tan x/y)/dx
=(1/tan( x/y)) *d (tan x/y)/dx
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*dx/y
=2 /[y *sin(2x/y)]
dz/dy =d (ln tan x/y)/dy
=(1/tan( x/y)) *d (tan x/y)/dy
=(1/tan( x/y)) *sec^2( x/y)*d(x/y)
=(1/tan( x/y)) *sec^2( x/y)*(-x/y^2)
= - 2x/[y^2*sin(2x/y)]
设y=ln(xy)求偏导数∂z/∂x
求z=ln(x^2y-lny) 的 一阶偏导数
ln(x-y)二次导数怎么求
求函数Z=ln(x^2+y^2)的偏导数az/ax...和a^2z/ax^2
高等数学求偏导数设z=z(x,y)由方程lnx+xyz+lnz=0确定,求偏z/偏y.
y=ln tan(x/2) -cosx*ln tanx; arctan(x+1/x-1) 的导数 求有详解
求y=Ln(Ln(Ln x))的导数
帮忙解一道高数题y=ln(sec x + tan x)求“y=ln(sec x + tan x)”的导数
求函数y=ln[tan(x/2)]-[cosx/3(sinx)^3]的导数,
多元隐函数求导设x/y=ln(z/y),求z对x的导数,要详解,
函数z=ln(x+y/2x),则偏导数az/ay=
已知x/z=ln(z/y),求z对x和y的偏导.