若sin(θ-π)=2cos(2π-θ)求(1)sinθ+5cosθ/sinθ-3cosθ (2)sinθcosθ的值
求证:(1+cosθ+cosθ/2) /(sinθ+sinθ/2)=sinθ/1-cosθ
求证(1+sinθ+cosθ)/(1+sinθ-cosθ)+(1-cosθ+sinθ)/(1+cosθ+sinθ)=2/
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
已知tanθ=根号2,求(1)(cosθ+sinθ)/(cosθ-sinθ);(2)sin²θ-sinθcos
sin(π-θ)+cos(2π-θ)/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____
已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos
已知2sinθ+3cosθ=2,求sinθ+cosθ的值
θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小
化简:1+sinθ+cosθ+2sinθcosθ /1+sinθ+cosθ
已知tanθ=3,求(3cosθ-5sin^2θcosθ)/sin(π-θ)的值
已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4)
已知sin(θ+kπ)=2cos[θ+(k+1)π],k∈Ζ,求4sinθ-2cosθ/5cosθ+3sinθ的值