y=sin(π/4-2x)和y=cos(2x-π/3)求单调增区间.
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y=sin(π/4-2x)和y=cos(2x-π/3)求单调增区间.
y=sin(π/4-2x)单调增区间为
π/4-2x∈[2kπ-π/2,2kπ+π/2] (k∈Z)
-2x∈[2kπ-3π/4,2kπ+π/4] (k∈Z)
解得
x∈[kπ-π/8,2kπ+3π/8](k∈Z)
y=cos(2x-π/3)单调增区间为
2x-π/3∈[2kπ-π,2kπ] (k∈Z)
2x∈[2kπ-2π/3,2kπ+π/3] (k∈Z)
解得
x∈[kπ-π/3,kπ+π/6](k∈Z)
再问: y=-2sin(x+π/4)-1和y=sin²x-sinx+1当x∈R或x∈[π/2,π]时的最值分别是
再答: 额 好多 先把这道题采纳 再开一道题 求助我 给你解答
π/4-2x∈[2kπ-π/2,2kπ+π/2] (k∈Z)
-2x∈[2kπ-3π/4,2kπ+π/4] (k∈Z)
解得
x∈[kπ-π/8,2kπ+3π/8](k∈Z)
y=cos(2x-π/3)单调增区间为
2x-π/3∈[2kπ-π,2kπ] (k∈Z)
2x∈[2kπ-2π/3,2kπ+π/3] (k∈Z)
解得
x∈[kπ-π/3,kπ+π/6](k∈Z)
再问: y=-2sin(x+π/4)-1和y=sin²x-sinx+1当x∈R或x∈[π/2,π]时的最值分别是
再答: 额 好多 先把这道题采纳 再开一道题 求助我 给你解答
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