化简 1-sin^4x-cos^4x/1-sin^6x-cos^6x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简(1)√3sin x+cos x (2)√2(sin x-cos x) (3)√2cos x-√6sin x
三角等式求证:cos^6x+sin^6x=1-3sin^2x+3sin^4x
求证(cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2
sin(1/x)-cos(1/x)/x
(1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
函数f(x)=-√2(sin2x+π/4)+6 sin x cos x-2cos²x+1
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
2cos x (sin x -cos x)+1
f x =sin(pai*x/4-pai/6)-2(cos pai*x/8)^2+1
三角函数证明及化简题1.证明sin^6x+cos^6x=(sin^2x+cos^2x)(cos^4x-cos^2xsin