2y+1/4+10y+1/6=1-1-2y/3
解3y+5/3y-6=1/2+5y-4/2y-4
{3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1
在y=1,y=2,y=3中,_________方程y=10-4y的解
解方程:3y^2-(2y+1)(y-1)=(y-5)(y+1)
解方程3y^2-(2y+1)(y-2)=(y-5)(y-1)
[(2x+y)^2+(y+2x)(y-2x)-2y(4x-y)]/4y,其中x=1/2,y=1/3
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
解方程,3y^3+(y+3)(6-2y)+3y(y+2)(2-y)-2(y^2+1)=0
微分方程(1)(y'')^2+5y'-y+x=0;(2)y''+5y'+4y^2-8x=0;(3)(3x+2y)dx+(
先化简,再求值:[(x+y)(x-y)-(x-y)^2+2y(x-3y)]/(-4y),其中x=1,y=-2
已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0
因式分解 (1)6(x-y)^3-3y(y-x)^2 (2)x(x-y)(a-b)-y(y-x)(