若a"填空(1)a+1()b+1 (2)a-5()b-5 (3)-3a()-3b (4)6-a()6-b
因式分解:(a+1)(a+3)(a+5)(a+7)+15 a(a-b+2)-6b(b+1)
(3a-6b)/(a+b) - (5a-6b)/(a-b) - (4a-5b)/(a+b) - (7a-8b)/(a-b
(3a-6b/a+b)-(5a-6b/a-b)-(4a-5b/a+b)-(7a-8b/b-a)
若a,b满足|a+5b-2|+(a+b-6)²=0,求代数式(a-3b)(a+2b)-(a+5b)(a+3b)
用简便方法计算 (1)(3a-6b/a+b-(5a-6b/a-b)-(4a-5b/a+b)-(7a-8b/b-a) 第二
已知:a-b=1/6 a²-b²=1/3 求代数式a(3a+5b)-(a-b)(a+2b)
先化简,再求值:(2a-b)^2-(2a+b)(a-b)-3(a-3b)(a+3b),其中|a-1|+b^2=6b-9
a-b\a+b=1\2时,求代数式a+b\3(a-b) - a-b\2(a+b)
(3a+2b)(6a-5b)(2b-3a)(5a+6b)
分解因式(a+1)(a+3)(a+5)(a+7)+15(2a+b)(4a^2-2ab+b^2)-b(2a-b)^2a^3
化简 (a+b)²+2a(a-1/2b)-3(a-b)(a+b)
b/(a+c)=1/2,a/(b+c)=1/5 怎么得出a/(a+b+c)=1/6,b/(a+b+c)=1/3?