如图,已知AC=AB、AE=AD,∠EAB=∠DAC,求证:BD=CE.
如图,在△ABC中,AB=AC,AD⊥BD,AE⊥CE,且AD=AE,BD和CE交于点O.说明∠EAB=∠DAC
已知:如图.AB=AC,AE=AD,BD=EC,求证:∠BAE=∠DAC
如图,已知AB=AC,AD=AE.求证:BD=CE.
已知:如图,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图,AB=AC,AD=AE,角EAB=角DAC.角D=角E.
已知:如图,AE=AC,AB=AD,∠EAB=∠CAD 已知:如图,AE=AC,AB=AD,∠EAB=∠CAD
已知如图,AE=AC,∠E=∠C,∠EAB=∠CAD,求证:AB=AD
如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗?为什么?
如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗?为什么?
如图,已知AB=AC,AE=AD,∠EAB=∠DAC,那么BE与CD相等吗,为什么
如图,已知AB=AC,AD=AE,BD=CE,求证:∠3=∠1+∠2
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE