139x137/138+137x1/138

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/05/17 20:32:48

139x137/138+137x1/138
奥数减算：1993x1994-1/1993+1992x1994

139x137/138+137x1/138
=(138+1)x(138-1)/138+137x1/138
=(138^2-1)/138+137x1/138
=138^2/138+(137-1)/138
=138+136/138
=138+68/69
=138又69分之68
1993x1994-1/1993+1992x1994
分子=1993x(1993+1)-1
=1993^2+1993-1
=1993^2+1992
分母=1993+(1993-1)x(1993+1)
=1993+1993^2-1
=1993^2+1992
所以1993x1994-1/1993+1992x1994=1

已知x1,x2(x1 若x1,x2(x1 设x1,x2(x1 137x135/136+135x1/136 如何简算? 定义区间[x1,x2](x1 定义：区间[x1,x2]( x1 1.1x1.1x1.1-1.1x1.1-0.11 m-X1^2/4=X1/2(X0-X1) 简算1.1x1.1x1.1-1.1x1.1-0.11! X2/X1(X1+X2)+X3/(X1+X2)(X1+X2+X3)+.Xn/（x1+x2+...Xn-1)(X1+X2. x1,x2,.x9是正整数,且x1 1x1\3+2x1\4+3x1\5+.+2006x1\2008的简便算法