6、用配方法解下列方程x2-6x=-5 y2+3y-2=0 a2=6a-1 x2-4x+3=0 2y2+8y+7=0 -
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/16 01:45:10
6、用配方法解下列方程x2-6x=-5 y2+3y-2=0 a2=6a-1 x2-4x+3=0 2y2+8y+7=0 - x2-3x=1
(1)x2-6x=-5 (2、) y2+3y-2=0 (3) a2=6a-1 (4) x2-4x+3=0 (5) 2y2+8y+7=0 (6) - x2-3x=1
(1)x2-6x=-5 (2、) y2+3y-2=0 (3) a2=6a-1 (4) x2-4x+3=0 (5) 2y2+8y+7=0 (6) - x2-3x=1
x2-6x=-5
x2-6x+9=-5+9
(x-3)²=4
x-3=±2
x1=1
x2=5
y2+3y-2=0
y2+3y+2.25=2+2.25
(y+1.5)²=4.25
y+1.5=±0.5√17
y1=0.5√17-1.5
y2=-0.5√17-1.5
a2-6a=-1
a2-6a+9=-1+9
(a-3)²=8
a-2=±2√2
a1=2+2√2
a2=2-2√2
x2-4x+3=0
x2-4x+3+1=1
x2-4x+4=1
(x-2)²=1
x-2=±1
x1=1
x2=3
2y2+8y+7=0
y²+4y+3.5=0
y²+4y+3.5+0.5=0.5
y²+4y+4=0.5
(y+2)²=0.5
y+2=±√2/2
y1=√2/2 -2
y2=-√2/2 -2
- x2-3x=1
x2+3x=-1
x2+3x+2.25=-1+2.25
(x+1.5)²=1.25
x+1.5=±0.5√5
x1=√5 /2 -1.5
x2=-√5 /2 -1.5
x2-6x+9=-5+9
(x-3)²=4
x-3=±2
x1=1
x2=5
y2+3y-2=0
y2+3y+2.25=2+2.25
(y+1.5)²=4.25
y+1.5=±0.5√17
y1=0.5√17-1.5
y2=-0.5√17-1.5
a2-6a=-1
a2-6a+9=-1+9
(a-3)²=8
a-2=±2√2
a1=2+2√2
a2=2-2√2
x2-4x+3=0
x2-4x+3+1=1
x2-4x+4=1
(x-2)²=1
x-2=±1
x1=1
x2=3
2y2+8y+7=0
y²+4y+3.5=0
y²+4y+3.5+0.5=0.5
y²+4y+4=0.5
(y+2)²=0.5
y+2=±√2/2
y1=√2/2 -2
y2=-√2/2 -2
- x2-3x=1
x2+3x=-1
x2+3x+2.25=-1+2.25
(x+1.5)²=1.25
x+1.5=±0.5√5
x1=√5 /2 -1.5
x2=-√5 /2 -1.5
已知x2+y2+4x-6y+13=0 求x2-2x\x2+3y2
用配方法解下列方程①x2-2x=2x+1②y2-4√3y+12=0③2x2+1=3x④﹙x-3﹚﹙2x+1﹚=-5
解方程:(1)x2-6x+9=(5-2x)2;(2)2y2+8y-1=0(用配方法).
用配方法解一元二次方程(1)x2+2x-8=0 (2)x2-4=2x (3)3y2-6y-24=0 (4)4x2-7x+
X2+Y2+8X+6Y+25=0 求代数式(x2-4y2/x2+4xy+4y2)-x/x+2y
已知X2+Y2+8X+6Y+25=0 求代数式X2++XY+4Y2分之X2-4Y2 减X+2Y分之X的值
用配方法解方程.(1)x2+2x-5=0;(2)x2+22x-240=0;(3)x2-8x+15=0;(4)-y2+2y
用配方法解下列方程①x2-2x-2=0②x2+8x-9=0③2x2+1=-3x④3x2-6x+4=0
已知方程x2 +y2+4x-2y-4=0,求x2 +y2的最大值
已知x2+4y2+x2y2-6xy+1=0,求 x4-y4/2x-y 乘 2xy-y2/xy-y2 除以(x2+y2/x
若X2+Y2-2X-6Y+10=0 ,求(x2-y2)/xy的值
已知x,y满足x2+y2-6x-2y+5=0,求x2+y2的最大值