谁会因式分解呀 1.x4-12x+3232.x4+7x3+14x2+7x+13.x4-11x2y2+y24.(x+3)(
来源:学生作业帮 编辑:作业帮 分类:数学作业 时间:2024/05/22 12:35:05
谁会因式分解呀
1.x4-12x+323
2.x4+7x3+14x2+7x+1
3.x4-11x2y2+y2
4.(x+3)(x2-1)(x+5)-20
1.x4-12x+323
2.x4+7x3+14x2+7x+1
3.x4-11x2y2+y2
4.(x+3)(x2-1)(x+5)-20
2.x4+7x3+14x2+7x+1
=x²(x²+7x+14+7/x+1/x²)
=x²[x²+1/x²+7x+7/x+14]
=x²[(x+1/x)²+7(x+1/x)+12]
=x²(x+1/x+3)(x+1/x+4)
=(x²+3x+1)(x²+4x+1)
3.
令x4-11x2y2+y2=0
△=121y4-4y²=y²(121y²-4)
∴x²=11y²-y√(121y²-4)或11y²+y√(121y²-4)
∴原式=(x²-11y²+y√(121y²-4))(x²-11y²-y√(121y²-4))
4.
(x+3)(x2-1)(x+5)-20
=(x-1)(x+1)(x+3)(x+5)-20
=(x²+4x-5)(x²+4x+3)-20
=(x²+4x)²-2(x²+4x)-35
=(x²+4x-7)(x²+4x+5)
=x²(x²+7x+14+7/x+1/x²)
=x²[x²+1/x²+7x+7/x+14]
=x²[(x+1/x)²+7(x+1/x)+12]
=x²(x+1/x+3)(x+1/x+4)
=(x²+3x+1)(x²+4x+1)
3.
令x4-11x2y2+y2=0
△=121y4-4y²=y²(121y²-4)
∴x²=11y²-y√(121y²-4)或11y²+y√(121y²-4)
∴原式=(x²-11y²+y√(121y²-4))(x²-11y²-y√(121y²-4))
4.
(x+3)(x2-1)(x+5)-20
=(x-1)(x+1)(x+3)(x+5)-20
=(x²+4x-5)(x²+4x+3)-20
=(x²+4x)²-2(x²+4x)-35
=(x²+4x-7)(x²+4x+5)
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