若sin(π/6+α)=3/5,则cos(π/3-α)=?
若(sinα+cosα)/(sinα-cosα)=2 则sin(α-5π)·sin(3π/2-α)=?
若sinα+cosαsinα−cosα=2,则sin(α-5π)•sin(3π2-α)等于( )
已知(sinα-cosα)/(sinα+cosα)=1/3,则cos^4(π/3+α)-cos^4(π/6-α)的值为
已知(3sinα+cosα)/(3cosα-sinα)=2,则2-3sin(α-3π)sin(1.5π-α)-[cos(
sin²α+√3sinαcosα-2cos²α=0,α∈(π/6,5π/12),求:(1)sin(2
三角函数题2sin^2α-cos^α+sinα*cosα-6sinα+3cosα=0 求(2cos^α+2sinαcos
已知cos(α-π/6)+sinα=4/5 根号3,则sin(α+7/6π)=?
已知cos(α-π/6)+sinα=(4倍根号3)/5,则sin(α+7π/6)=
已知(sinα+3cosα)/(3cosα-sinα)=5 则sin^2α-sinαcosα的值是
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
化简:sin(π/4-α)cos(π/3-α)-cos(π/6+α)sin(π/4+α)=
已知(2sinα+cosα)/(sinα-3cosα)=-5,则2cos^2α+sin2α