A wire of 53 cm long is cut into two parts.The longer wire i

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A wire of 53 cm long is cut into two parts.The longer wire is bent to form an equilateral triangle.The shorter one is bent to form a square.If the length of each side of the square is 6 cm shorter than that of the triangle,find the respective lengths of the longer and shorter wires.

let X be the length of the triangle
3(X+6)+4X=53
3X+18+4X=53
7X =53-18
7X=35
X=5
the length of the shorter wire is
5cm×4＝20cm
the length of the loner wire is
(5+6) ×3= 33cm

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