[(2X+Y)*(2X+Y)-Y(Y+4X)]/2X 怎么算?

x^2-y^2/x+y-4x(x-y)+y^2/2x-y, 1、x(x-y)(x+y)-x(x+y)^2 2xy/(x+y)(x+y)与x/(x+y)(x-y)怎么通分 (2x-y)^2-4(x-y)(x+2y) (2x-y)²-4(x-y)(x+2y) 化简：（2x-y)²-4(x-y)(x+y) {(z+y)(x-y)-(x-y)的2次方+2y(x-y)}除以4y x+2y+4y^2/x-y+4x^y/4y^2-x^2 (1)(x^2/x)-y-x-y 4x(y-x)-y^2因式分解 (x+3y-4)(2x-y) 【(x-y)^2+(x+y)(x-y)】除以 2x