lim [2^(n+2)+3^(n+3)] / [3^n-2^(n+1)] 如何计算?
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim根号n^2+n+1/3n-2
lim n->无穷大(2^n-1)/(3^n+1)
lim(3^2n+5^n)/(1+9^n)
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lim(n→∞)[1/(3n+1)+1/(3n+2)+~1/(3n+n)]
lim n趋于无穷大(1/n^2+3/n^2+.+2n-1/n^2
lim(1/n^2+4/n^2+7/n^2+…+3n-1/n^2)
求极限lim [ 2^(n+1)+3^(n+1)]/2^n+3^n (n→∞)
求lim(n+1)(n+2)(n+3)/(n^4+n^2+1)
一道极限题,lim[n^2(2n+1)]/(n^3+n+4)n->∞