若x²+y²-2x=0,求u=2x²-x+y²范围
已知x²+y²-2x+4y=0,求x+3y的取值范围?
若y=x²-2x(0≤x≤m),求y的取值范围
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.
若|x+2y-1|+y²+4y+4=0,求(2x-y)²-2(2x-y)(x+2y)+(x+2y)&
已知x/y=2,求2x(x+y)-y(x+y)/4x²-4xy+y²
求函数y=x²-x-2自变量x的取值范围
已知实数x,y满足x²+y²=1.求x²-4x+y²+2y的取值范围,求详解,
1、已知x²+y²/4=1,求3x+2y的范围
y=x²-2x+3,求y取值范围
已知实数X,Y满足X²+Y²+4X+3=0,求Y-2/X-1的取值范围.
已知x²+y²+5=2x+4y,求【2x²-(x-y)(x-y)】【(x+y-1)(x-y
已知x²+y²+13-4x+6y=0,求(2x-y)²-2(2x-y)(x+2y)+(x+